By Sunil Bhardwaj

3527 Views

According to Freezing Point Depression relation, $$\boxed { \Delta { T }_{ f } = K_{ f } \times m }$$ Lets substitute the value to molality m, $$\Delta { T }_{ f } = K_{ f } \times \frac { W_{ 2 } }{ W_{ 1 }M_{ 2 } } \times 1000$$ $$\therefore \boxed { M_{ 2 } = \frac { 1000W_{ 2 }K_{ f } }{ \Delta { T }_{ f }W_{ 1 } } }$$ Thus, by determining the depression in freezing point of the solution it is possible to calculate the molecular weight of the dissolved solute.